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136723730540437 = 904706315112499
BaseRepresentation
bin11111000101100101111001…
…011001000010011110010101
3122221002122211212020121002001
4133011211321121002132111
5120410040200004243222
61202442003102115301
740540651333256365
oct3705457131023625
9587078755217061
10136723730540437
113a623232567567
1213401b8487bb31
135b39cb95b4401
1425a966cbc89a5
1510c1770aeee27
hex7c5979642795

136723730540437 has 4 divisors (see below), whose sum is σ = 136723754700000. Its totient is φ = 136723706380876.

The previous prime is 136723730540407. The next prime is 136723730540447. The reversal of 136723730540437 is 734045037327631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136723730540437 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136723730540407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1490814 + ... + 16603312.

It is an arithmetic number, because the mean of its divisors is an integer number (34180938675000).

Almost surely, 2136723730540437 is an apocalyptic number.

It is an amenable number.

136723730540437 is a deficient number, since it is larger than the sum of its proper divisors (24159563).

136723730540437 is an equidigital number, since it uses as much as digits as its factorization.

136723730540437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24159562.

The product of its (nonzero) digits is 26671680, while the sum is 55.

The spelling of 136723730540437 in words is "one hundred thirty-six trillion, seven hundred twenty-three billion, seven hundred thirty million, five hundred forty thousand, four hundred thirty-seven".

Divisors: 1 9047063 15112499 136723730540437