Base | Representation |
---|---|
bin | 11111000110000011000111… |
… | …011100011001010010000101 |
3 | 122221012122211101110211122220 |
4 | 133012003013130121102011 |
5 | 120411043423313023323 |
6 | 1202504232225442553 |
7 | 40543141661222334 |
oct | 3706030734312205 |
9 | 587178741424586 |
10 | 136755104814213 |
11 | 3a635572518846 |
12 | 1340807baa0459 |
13 | 5b3cc495bb352 |
14 | 25aada7969d1b |
15 | 10c24aa1db0e3 |
hex | 7c60c7719485 |
136755104814213 has 4 divisors (see below), whose sum is σ = 182340139752288. Its totient is φ = 91170069876140.
The previous prime is 136755104814203. The next prime is 136755104814221. The reversal of 136755104814213 is 312418401557631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 136755104814213 - 24 = 136755104814197 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136755104814203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22792517469033 + ... + 22792517469038.
It is an arithmetic number, because the mean of its divisors is an integer number (45585034938072).
Almost surely, 2136755104814213 is an apocalyptic number.
It is an amenable number.
136755104814213 is a deficient number, since it is larger than the sum of its proper divisors (45585034938075).
136755104814213 is an equidigital number, since it uses as much as digits as its factorization.
136755104814213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45585034938074.
The product of its (nonzero) digits is 2419200, while the sum is 51.
The spelling of 136755104814213 in words is "one hundred thirty-six trillion, seven hundred fifty-five billion, one hundred four million, eight hundred fourteen thousand, two hundred thirteen".
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