Base | Representation |
---|---|
bin | 1100011100010100100101… |
… | …1101111110111001111111 |
3 | 1210102212021202002211022101 |
4 | 3013011021131332321333 |
5 | 3243121040034344432 |
6 | 45032454533325531 |
7 | 2611253404335154 |
oct | 307051135767177 |
9 | 53385252084271 |
10 | 13680703434367 |
11 | 43a4a54484a92 |
12 | 164b4b3a968a7 |
13 | 7831143c0088 |
14 | 35421463422b |
15 | 18acee6234e7 |
hex | c714977ee7f |
13680703434367 has 4 divisors (see below), whose sum is σ = 13691889619920. Its totient is φ = 13669517248816.
The previous prime is 13680703434271. The next prime is 13680703434371. The reversal of 13680703434367 is 76343430708631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13680703434367 - 219 = 13680702910079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13680703434067) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5593090942 + ... + 5593093387.
It is an arithmetic number, because the mean of its divisors is an integer number (3422972404980).
Almost surely, 213680703434367 is an apocalyptic number.
13680703434367 is a deficient number, since it is larger than the sum of its proper divisors (11186185553).
13680703434367 is a wasteful number, since it uses less digits than its factorization.
13680703434367 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11186185552.
The product of its (nonzero) digits is 18289152, while the sum is 55.
The spelling of 13680703434367 in words is "thirteen trillion, six hundred eighty billion, seven hundred three million, four hundred thirty-four thousand, three hundred sixty-seven".
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