Base | Representation |
---|---|
bin | 11111000110110111001100… |
… | …101100101011100100101111 |
3 | 122221102000011201221212122211 |
4 | 133012313030230223210233 |
5 | 120413002441022404432 |
6 | 1202550041323551251 |
7 | 40550161541461051 |
oct | 3706671454534457 |
9 | 587360151855584 |
10 | 136811027544367 |
11 | 3a65725a435700 |
12 | 13416a8838b527 |
13 | 5b452bc411317 |
14 | 25ad990b138d1 |
15 | 10c3b7ea03d47 |
hex | 7c6dccb2b92f |
136811027544367 has 12 divisors (see below), whose sum is σ = 150411203102160. Its totient is φ = 124347079640960.
The previous prime is 136811027544277. The next prime is 136811027544383. The reversal of 136811027544367 is 763445720118631.
It is a de Polignac number, because none of the positive numbers 2k-136811027544367 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136811027544067) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 120257698 + ... + 121390015.
It is an arithmetic number, because the mean of its divisors is an integer number (12534266925180).
Almost surely, 2136811027544367 is an apocalyptic number.
136811027544367 is a deficient number, since it is larger than the sum of its proper divisors (13600175557793).
136811027544367 is a wasteful number, since it uses less digits than its factorization.
136811027544367 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 241652414 (or 241652403 counting only the distinct ones).
The product of its (nonzero) digits is 20321280, while the sum is 58.
The spelling of 136811027544367 in words is "one hundred thirty-six trillion, eight hundred eleven billion, twenty-seven million, five hundred forty-four thousand, three hundred sixty-seven".
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