Base | Representation |
---|---|
bin | 110100001101… |
… | …011000011101 |
3 | 221202100002001 |
4 | 310031120131 |
5 | 12000430201 |
6 | 1205202301 |
7 | 224221516 |
oct | 64153035 |
9 | 27670061 |
10 | 13686301 |
11 | 77a87a2 |
12 | 4700391 |
13 | 2ab2705 |
14 | 1b63a0d |
15 | 1305301 |
hex | d0d61d |
13686301 has 4 divisors (see below), whose sum is σ = 13693792. Its totient is φ = 13678812.
The previous prime is 13686287. The next prime is 13686307. The reversal of 13686301 is 10368631.
13686301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 13686301 - 25 = 13686269 is a prime.
It is a super-3 number, since 3×136863013 (a number of 22 digits) contains 333 as substring.
It is the 3700-th Hogben number.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13686301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13686307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000 + ... + 5326.
It is an arithmetic number, because the mean of its divisors is an integer number (3423448).
Almost surely, 213686301 is an apocalyptic number.
It is an amenable number.
13686301 is a deficient number, since it is larger than the sum of its proper divisors (7491).
13686301 is an equidigital number, since it uses as much as digits as its factorization.
13686301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7490.
The product of its (nonzero) digits is 2592, while the sum is 28.
The square root of 13686301 is about 3699.5001013650. The cubic root of 13686301 is about 239.2004702119.
It can be divided in two parts, 1368630 and 1, that added together give a palindrome (1368631).
The spelling of 13686301 in words is "thirteen million, six hundred eighty-six thousand, three hundred one".
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