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13691252903 = 23957285577
BaseRepresentation
bin11001100000000111…
…11111000010100111
31022100011111201011212
430300003333002213
5211014430043103
610142323022035
7663165505136
oct146003770247
938304451155
1013691252903
11589639aa49
1227a120a91b
1313a266a8a3
1493c4a791d
15551e977d8
hex3300ff0a7

13691252903 has 4 divisors (see below), whose sum is σ = 13748538720. Its totient is φ = 13633967088.

The previous prime is 13691252893. The next prime is 13691252929. The reversal of 13691252903 is 30925219631.

13691252903 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13691252903 - 28 = 13691252647 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13691257903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28642550 + ... + 28643027.

It is an arithmetic number, because the mean of its divisors is an integer number (3437134680).

Almost surely, 213691252903 is an apocalyptic number.

13691252903 is a deficient number, since it is larger than the sum of its proper divisors (57285817).

13691252903 is an equidigital number, since it uses as much as digits as its factorization.

13691252903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57285816.

The product of its (nonzero) digits is 87480, while the sum is 41.

The spelling of 13691252903 in words is "thirteen billion, six hundred ninety-one million, two hundred fifty-two thousand, nine hundred three".

Divisors: 1 239 57285577 13691252903