Base | Representation |
---|---|
bin | 11111001001001011011100… |
… | …100000011010110100011010 |
3 | 122221222020001012100110112122 |
4 | 133021023130200122310122 |
5 | 120423104440334233133 |
6 | 1203151124430341242 |
7 | 40564525255652345 |
oct | 3711133440326432 |
9 | 587866035313478 |
10 | 136970206555418 |
11 | 3a7088138816a5 |
12 | 134418b105a822 |
13 | 5b57309559762 |
14 | 25b757159745c |
15 | 10c7d99370498 |
hex | 7c92dc81ad1a |
136970206555418 has 4 divisors (see below), whose sum is σ = 205455309833130. Its totient is φ = 68485103277708.
The previous prime is 136970206555417. The next prime is 136970206555447. The reversal of 136970206555418 is 814555602079631.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 105736448849329 + 31233757706089 = 10282823^2 + 5588717^2 .
It is not an unprimeable number, because it can be changed into a prime (136970206555411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34242551638853 + ... + 34242551638856.
It is a 1-persistent number, because it is pandigital, but 2⋅136970206555418 = 273940413110836 is not.
Almost surely, 2136970206555418 is an apocalyptic number.
136970206555418 is a deficient number, since it is larger than the sum of its proper divisors (68485103277712).
136970206555418 is an equidigital number, since it uses as much as digits as its factorization.
136970206555418 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68485103277711.
The product of its (nonzero) digits is 54432000, while the sum is 62.
The spelling of 136970206555418 in words is "one hundred thirty-six trillion, nine hundred seventy billion, two hundred six million, five hundred fifty-five thousand, four hundred eighteen".
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