Base | Representation |
---|---|
bin | 11111001011100110010101… |
… | …000011001101101010010010 |
3 | 122222120010022021100000100220 |
4 | 133023212111003031222102 |
5 | 120433321033412112204 |
6 | 1203355351005253510 |
7 | 40612533411113652 |
oct | 3713462503155222 |
9 | 588503267300326 |
10 | 137136511441554 |
11 | 3a7722a4627059 |
12 | 13469b84264296 |
13 | 5b69bc0ab0c21 |
14 | 25c162a5a2362 |
15 | 10cc37e5bc1d9 |
hex | 7cb9950cda92 |
137136511441554 has 16 divisors (see below), whose sum is σ = 286197936921792. Its totient is φ = 43724684807408.
The previous prime is 137136511441469. The next prime is 137136511441583. The reversal of 137136511441554 is 455144115631731.
It is a junction number, because it is equal to n+sod(n) for n = 137136511441497 and 137136511441506.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 496871418129 + ... + 496871418404.
It is an arithmetic number, because the mean of its divisors is an integer number (17887371057612).
Almost surely, 2137136511441554 is an apocalyptic number.
137136511441554 is an abundant number, since it is smaller than the sum of its proper divisors (149061425480238).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
137136511441554 is a wasteful number, since it uses less digits than its factorization.
137136511441554 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 993742836561.
The product of its digits is 3024000, while the sum is 51.
The spelling of 137136511441554 in words is "one hundred thirty-seven trillion, one hundred thirty-six billion, five hundred eleven million, four hundred forty-one thousand, five hundred fifty-four".
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