Base | Representation |
---|---|
bin | 10011111101001111000… |
… | …001011011111101000011 |
3 | 11212002212122022211221221 |
4 | 103331033001123331003 |
5 | 134432132102003011 |
6 | 2530004413255511 |
7 | 201040034405125 |
oct | 23751701337503 |
9 | 4762778284857 |
10 | 1371420344131 |
11 | 489686038892 |
12 | 1a1959a94597 |
13 | 9c42a8944b6 |
14 | 4a53ca8b215 |
15 | 25a19098971 |
hex | 13f4f05bf43 |
1371420344131 has 4 divisors (see below), whose sum is σ = 1371846122064. Its totient is φ = 1370994566200.
The previous prime is 1371420344093. The next prime is 1371420344143. The reversal of 1371420344131 is 1314430241731.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1371420344131 - 225 = 1371386789699 is a prime.
It is a super-2 number, since 2×13714203441312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1371420744131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212884135 + ... + 212890576.
It is an arithmetic number, because the mean of its divisors is an integer number (342961530516).
Almost surely, 21371420344131 is an apocalyptic number.
1371420344131 is a deficient number, since it is larger than the sum of its proper divisors (425777933).
1371420344131 is an equidigital number, since it uses as much as digits as its factorization.
1371420344131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 425777932.
The product of its (nonzero) digits is 24192, while the sum is 34.
Adding to 1371420344131 its reverse (1314430241731), we get a palindrome (2685850585862).
The spelling of 1371420344131 in words is "one trillion, three hundred seventy-one billion, four hundred twenty million, three hundred forty-four thousand, one hundred thirty-one".
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