Base | Representation |
---|---|
bin | 10011111101010010000… |
… | …111110011010100110011 |
3 | 11212010000021011201212202 |
4 | 103331102013303110303 |
5 | 134432233410004441 |
6 | 2530013512013415 |
7 | 201041235403253 |
oct | 23752207632463 |
9 | 4763007151782 |
10 | 1371472344371 |
11 | 489702425398 |
12 | 1a197339126b |
13 | 9c4385a017c |
14 | 4a545945963 |
15 | 25a1d91b19b |
hex | 13f521f3533 |
1371472344371 has 4 divisors (see below), whose sum is σ = 1374596427600. Its totient is φ = 1368348261144.
The previous prime is 1371472344301. The next prime is 1371472344383. The reversal of 1371472344371 is 1734432741731.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1371472344371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1371472344301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1562040956 + ... + 1562041833.
It is an arithmetic number, because the mean of its divisors is an integer number (343649106900).
Almost surely, 21371472344371 is an apocalyptic number.
1371472344371 is a deficient number, since it is larger than the sum of its proper divisors (3124083229).
1371472344371 is an equidigital number, since it uses as much as digits as its factorization.
1371472344371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3124083228.
The product of its digits is 1185408, while the sum is 47.
The spelling of 1371472344371 in words is "one trillion, three hundred seventy-one billion, four hundred seventy-two million, three hundred forty-four thousand, three hundred seventy-one".
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