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13725593439 = 38951406717
BaseRepresentation
bin11001100100001101…
…11110111101011111
31022102120010101112120
430302012332331133
5211102222442224
610145551034023
7664063422255
oct146206767537
938376111476
1013725593439
115903815558
1227b080b913
1313a980242c
14942c865d5
15554ecc779
hex3321bef5f

13725593439 has 8 divisors (see below), whose sum is σ = 18506418480. Its totient is φ = 9047582016.

The previous prime is 13725593437. The next prime is 13725593461. The reversal of 13725593439 is 93439552731.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13725593439 - 21 = 13725593437 is a prime.

It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a junction number, because it is equal to n+sod(n) for n = 13725593391 and 13725593400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13725593437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25703092 + ... + 25703625.

It is an arithmetic number, because the mean of its divisors is an integer number (2313302310).

Almost surely, 213725593439 is an apocalyptic number.

13725593439 is a deficient number, since it is larger than the sum of its proper divisors (4780825041).

13725593439 is an equidigital number, since it uses as much as digits as its factorization.

13725593439 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51406809.

The product of its digits is 3061800, while the sum is 51.

The spelling of 13725593439 in words is "thirteen billion, seven hundred twenty-five million, five hundred ninety-three thousand, four hundred thirty-nine".

Divisors: 1 3 89 267 51406717 154220151 4575197813 13725593439