Base | Representation |
---|---|
bin | 11111001110011011001110… |
… | …100100111001011110111001 |
3 | 200000020200200002122021222212 |
4 | 133032123032210321132321 |
5 | 121000011334011221213 |
6 | 1204024513050024505 |
7 | 40632551003354000 |
oct | 3716331644713671 |
9 | 600220602567885 |
10 | 137330750101433 |
11 | 3a83770a255139 |
12 | 1349b752418135 |
13 | 5b823076061b5 |
14 | 25cabb543bc37 |
15 | 10d244bd4c9a8 |
hex | 7ce6ce9397b9 |
137330750101433 has 64 divisors (see below), whose sum is σ = 162621043200000. Its totient is φ = 115911914130432.
The previous prime is 137330750101399. The next prime is 137330750101459. The reversal of 137330750101433 is 334101057033731.
It is not a de Polignac number, because 137330750101433 - 212 = 137330750097337 is a prime.
It is not an unprimeable number, because it can be changed into a prime (137330750601433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9342856118 + ... + 9342870816.
It is an arithmetic number, because the mean of its divisors is an integer number (2540953800000).
Almost surely, 2137330750101433 is an apocalyptic number.
It is an amenable number.
137330750101433 is a deficient number, since it is larger than the sum of its proper divisors (25290293098567).
137330750101433 is a wasteful number, since it uses less digits than its factorization.
137330750101433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16339 (or 16325 counting only the distinct ones).
The product of its (nonzero) digits is 238140, while the sum is 41.
The spelling of 137330750101433 in words is "one hundred thirty-seven trillion, three hundred thirty billion, seven hundred fifty million, one hundred one thousand, four hundred thirty-three".
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