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137343763581 = 345781254527
BaseRepresentation
bin111111111101001010…
…0111000010001111101
3111010111201112002101120
41333322110320101331
54222240000413311
6143032253301153
712631335504543
oct1777224702175
9433451462346
10137343763581
1153279a79432
12227501947b9
13cc4a48c17b
14690c94bd93
15388c933706
hex1ffa53847d

137343763581 has 4 divisors (see below), whose sum is σ = 183125018112. Its totient is φ = 91562509052.

The previous prime is 137343763561. The next prime is 137343763591. The reversal of 137343763581 is 185367343731.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 137343763581 - 210 = 137343762557 is a prime.

It is a super-2 number, since 2×1373437635812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (137343763561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22890627261 + ... + 22890627266.

It is an arithmetic number, because the mean of its divisors is an integer number (45781254528).

Almost surely, 2137343763581 is an apocalyptic number.

It is an amenable number.

137343763581 is a deficient number, since it is larger than the sum of its proper divisors (45781254531).

137343763581 is an equidigital number, since it uses as much as digits as its factorization.

137343763581 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45781254530.

The product of its digits is 3810240, while the sum is 51.

The spelling of 137343763581 in words is "one hundred thirty-seven billion, three hundred forty-three million, seven hundred sixty-three thousand, five hundred eighty-one".

Divisors: 1 3 45781254527 137343763581