Base | Representation |
---|---|
bin | 10011111111101011001… |
… | …110101101001001101011 |
3 | 11212100122021200102110002 |
4 | 103333223032231021223 |
5 | 140003014003140024 |
6 | 2531120432413215 |
7 | 201162006241655 |
oct | 23775316551153 |
9 | 4770567612402 |
10 | 1374041068139 |
11 | 48a8003a85a3 |
12 | 1a236b6a720b |
13 | 9c75781226c |
14 | 4a70ab656d5 |
15 | 25b1e1be6ae |
hex | 13feb3ad26b |
1374041068139 has 4 divisors (see below), whose sum is σ = 1374433767000. Its totient is φ = 1373648369280.
The previous prime is 1374041068087. The next prime is 1374041068157. The reversal of 1374041068139 is 9318601404731.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1374041068139 - 212 = 1374041064043 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1374041068093 and 1374041068102.
It is not an unprimeable number, because it can be changed into a prime (1374041068339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196344182 + ... + 196351179.
It is an arithmetic number, because the mean of its divisors is an integer number (343608441750).
Almost surely, 21374041068139 is an apocalyptic number.
1374041068139 is a deficient number, since it is larger than the sum of its proper divisors (392698861).
1374041068139 is an equidigital number, since it uses as much as digits as its factorization.
1374041068139 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 392698860.
The product of its (nonzero) digits is 435456, while the sum is 47.
The spelling of 1374041068139 in words is "one trillion, three hundred seventy-four billion, forty-one million, sixty-eight thousand, one hundred thirty-nine".
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