Search a number
-
+
137473406802141 = 345824468934047
BaseRepresentation
bin11111010000100000000101…
…100101000001100011011101
3200000202022220002101112222120
4133100200011211001203131
5121004331014120132031
61204214224454133153
740646061114330264
oct3720400545014335
9600668802345876
10137473406802141
113a8921652408a3
12135033259511b9
135b928c0701437
1425d3a6982b5db
1510d5eeadeea96
hex7d08059418dd

137473406802141 has 4 divisors (see below), whose sum is σ = 183297875736192. Its totient is φ = 91648937868092.

The previous prime is 137473406802089. The next prime is 137473406802163. The reversal of 137473406802141 is 141208604374731.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 137473406802141 - 222 = 137473402607837 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (137473406802181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22912234467021 + ... + 22912234467026.

It is an arithmetic number, because the mean of its divisors is an integer number (45824468934048).

Almost surely, 2137473406802141 is an apocalyptic number.

It is an amenable number.

137473406802141 is a deficient number, since it is larger than the sum of its proper divisors (45824468934051).

137473406802141 is an equidigital number, since it uses as much as digits as its factorization.

137473406802141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45824468934050.

The product of its (nonzero) digits is 2709504, while the sum is 51.

The spelling of 137473406802141 in words is "one hundred thirty-seven trillion, four hundred seventy-three billion, four hundred six million, eight hundred two thousand, one hundred forty-one".

Divisors: 1 3 45824468934047 137473406802141