Base | Representation |
---|---|
bin | 10100000000110010010… |
… | …110111010010111010111 |
3 | 11212110201110011001102021 |
4 | 110000302112322113113 |
5 | 140012440001324001 |
6 | 2531435101554011 |
7 | 201233406353500 |
oct | 24006226722727 |
9 | 4773643131367 |
10 | 1375234401751 |
11 | 490262a70821 |
12 | 1a2643275907 |
13 | 9c8b7b11322 |
14 | 4a7c143bba7 |
15 | 25b8dd3eba1 |
hex | 140325ba5d7 |
1375234401751 has 12 divisors (see below), whose sum is σ = 1602942938352. Its totient is φ = 1176428839488.
The previous prime is 1375234401713. The next prime is 1375234401781. The reversal of 1375234401751 is 1571044325731.
It is not a de Polignac number, because 1375234401751 - 229 = 1374697530839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1375234401698 and 1375234401707.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1375234401781) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27873970 + ... + 27923263.
It is an arithmetic number, because the mean of its divisors is an integer number (133578578196).
Almost surely, 21375234401751 is an apocalyptic number.
1375234401751 is a deficient number, since it is larger than the sum of its proper divisors (227708536601).
1375234401751 is an equidigital number, since it uses as much as digits as its factorization.
1375234401751 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55797750 (or 55797743 counting only the distinct ones).
The product of its (nonzero) digits is 352800, while the sum is 43.
The spelling of 1375234401751 in words is "one trillion, three hundred seventy-five billion, two hundred thirty-four million, four hundred one thousand, seven hundred fifty-one".
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