Base | Representation |
---|---|
bin | 10100000011110111000… |
… | …100010101000010001101 |
3 | 11212210020110010121200101 |
4 | 110003313010111002031 |
5 | 140041214332014210 |
6 | 2533142353331101 |
7 | 201411242055556 |
oct | 24036704250215 |
9 | 4783213117611 |
10 | 1378534641805 |
11 | 4916a6959a42 |
12 | 1a3204566a91 |
13 | 9ccc27789a9 |
14 | 4aa1587b32d |
15 | 25cd393da3a |
hex | 140f711508d |
1378534641805 has 4 divisors (see below), whose sum is σ = 1654241570172. Its totient is φ = 1102827713440.
The previous prime is 1378534641767. The next prime is 1378534641821. The reversal of 1378534641805 is 5081464358731.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 181274132169 + 1197260509636 = 425763^2 + 1094194^2 .
It is not a de Polignac number, because 1378534641805 - 217 = 1378534510733 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137853464176 + ... + 137853464185.
It is an arithmetic number, because the mean of its divisors is an integer number (413560392543).
Almost surely, 21378534641805 is an apocalyptic number.
It is an amenable number.
1378534641805 is a deficient number, since it is larger than the sum of its proper divisors (275706928367).
1378534641805 is an equidigital number, since it uses as much as digits as its factorization.
1378534641805 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 275706928366.
The product of its (nonzero) digits is 9676800, while the sum is 55.
The spelling of 1378534641805 in words is "one trillion, three hundred seventy-eight billion, five hundred thirty-four million, six hundred forty-one thousand, eight hundred five".
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