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1379438899200 = 21233524143283
BaseRepresentation
bin10100000100101100111…
…101110011000000000000
311212212120110122122122000
4110010230331303000000
5140100042324233300
62533412214544000
7201442532115525
oct24045475630000
94785513578560
101379438899200
114920203299aa
121a3417368000
13a0107c0313b
144aa9d9c514c
1525d3800bc00
hex1412cf73000

1379438899200 has 1248 divisors, whose sum is σ = 5330634650880. Its totient is φ = 349293772800.

The previous prime is 1379438899193. The next prime is 1379438899219. The reversal of 1379438899200 is 29988349731.

1379438899200 is a `hidden beast` number, since 1 + 37 + 9 + 438 + 89 + 92 + 0 + 0 = 666.

It is a super-2 number, since 2×13794388992002 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4874342259 + ... + 4874342541.

Almost surely, 21379438899200 is an apocalyptic number.

1379438899200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1379438899200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2665317325440).

1379438899200 is an abundant number, since it is smaller than the sum of its proper divisors (3951195751680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1379438899200 is a wasteful number, since it uses less digits than its factorization.

1379438899200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 410 (or 377 counting only the distinct ones).

The product of its (nonzero) digits is 23514624, while the sum is 63.

The spelling of 1379438899200 in words is "one trillion, three hundred seventy-nine billion, four hundred thirty-eight million, eight hundred ninety-nine thousand, two hundred".