Base | Representation |
---|---|
bin | 1000000010000101110… |
… | …0110011001100111001 |
3 | 111012012110122001010210 |
4 | 2000201130303030321 |
5 | 4230111014320403 |
6 | 143221342101333 |
7 | 12653525634531 |
oct | 2004134631471 |
9 | 435173561123 |
10 | 138000151353 |
11 | 53586540269 |
12 | 228b3b7a849 |
13 | 1002346b7bc |
14 | 6971bb24c1 |
15 | 38ca38db03 |
hex | 2021733339 |
138000151353 has 4 divisors (see below), whose sum is σ = 184000201808. Its totient is φ = 92000100900.
The previous prime is 138000151339. The next prime is 138000151357. The reversal of 138000151353 is 353151000831.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 353151000831 = 3 ⋅117717000277.
It is not a de Polignac number, because 138000151353 - 210 = 138000150329 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 138000151353.
It is not an unprimeable number, because it can be changed into a prime (138000151357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23000025223 + ... + 23000025228.
It is an arithmetic number, because the mean of its divisors is an integer number (46000050452).
Almost surely, 2138000151353 is an apocalyptic number.
It is an amenable number.
138000151353 is a deficient number, since it is larger than the sum of its proper divisors (46000050455).
138000151353 is an equidigital number, since it uses as much as digits as its factorization.
138000151353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46000050454.
The product of its (nonzero) digits is 5400, while the sum is 30.
The spelling of 138000151353 in words is "one hundred thirty-eight billion, one hundred fifty-one thousand, three hundred fifty-three".
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