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1380479303845 = 5276095860769
BaseRepresentation
bin10100000101101010111…
…110101000000010100101
311212222020222100200111101
4110011222332220002211
5140104210200210340
62534103342240101
7201510364321315
oct24055276500245
94788228320441
101380479303845
1149250463a354
121a3667886031
13a02426190a5
144ab5bc4d445
1525d9951ec9a
hex1416afa80a5

1380479303845 has 4 divisors (see below), whose sum is σ = 1656575164620. Its totient is φ = 1104383443072.

The previous prime is 1380479303813. The next prime is 1380479303849. The reversal of 1380479303845 is 5483039740831.

It is a Cunningham number, because it is equal to 11749382+1.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 496971421444 + 883507882401 = 704962^2 + 939951^2 .

It is a cyclic number.

It is not a de Polignac number, because 1380479303845 - 25 = 1380479303813 is a prime.

It is a zygodrome in base 4.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1380479303849) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138047930380 + ... + 138047930389.

It is an arithmetic number, because the mean of its divisors is an integer number (414143791155).

Almost surely, 21380479303845 is an apocalyptic number.

It is an amenable number.

1380479303845 is a deficient number, since it is larger than the sum of its proper divisors (276095860775).

1380479303845 is an equidigital number, since it uses as much as digits as its factorization.

1380479303845 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 276095860774.

The product of its (nonzero) digits is 8709120, while the sum is 55.

The spelling of 1380479303845 in words is "one trillion, three hundred eighty billion, four hundred seventy-nine million, three hundred three thousand, eight hundred forty-five".

Divisors: 1 5 276095860769 1380479303845