1381888250007 has 4 divisors (see below), whose sum is σ = 1842517666680. Its totient is φ = 921258833336.

The previous prime is 1381888249999. The next prime is 1381888250011. The reversal of 1381888250007 is 7000528881831.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1381888250007 - 2³ = 1381888249999 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1381888250207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 230314708332 + ... + 230314708337.

It is an arithmetic number, because the mean of its divisors is an integer number (460629416670).

Almost surely, 2^{1381888250007} is an apocalyptic number.

1381888250007 is a deficient number, since it is larger than the sum of its proper divisors (460629416673).

1381888250007 is an equidigital number, since it uses as much as digits as its factorization.

1381888250007 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 460629416672.

The product of its (nonzero) digits is 860160, while the sum is 51.

The spelling of 1381888250007 in words is "one trillion, three hundred eighty-one billion, eight hundred eighty-eight million, two hundred fifty thousand, seven".