Base | Representation |
---|---|
bin | 10000011111101… |
… | …10101110011101 |
3 | 100122101010111122 |
4 | 20033312232131 |
5 | 240410432140 |
6 | 21421500325 |
7 | 3300105605 |
oct | 1017665635 |
9 | 318333448 |
10 | 138374045 |
11 | 71121517 |
12 | 3a4116a5 |
13 | 2288b244 |
14 | 1453dc05 |
15 | c234ab5 |
hex | 83f6b9d |
138374045 has 4 divisors (see below), whose sum is σ = 166048860. Its totient is φ = 110699232.
The previous prime is 138374021. The next prime is 138374081. The reversal of 138374045 is 540473831.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 95785369 + 42588676 = 9787^2 + 6526^2 .
It is a cyclic number.
It is not a de Polignac number, because 138374045 - 212 = 138369949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 138373996 and 138374014.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13837400 + ... + 13837409.
It is an arithmetic number, because the mean of its divisors is an integer number (41512215).
Almost surely, 2138374045 is an apocalyptic number.
It is an amenable number.
138374045 is a deficient number, since it is larger than the sum of its proper divisors (27674815).
138374045 is an equidigital number, since it uses as much as digits as its factorization.
138374045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27674814.
The product of its (nonzero) digits is 40320, while the sum is 35.
The square root of 138374045 is about 11763.2497635645. The cubic root of 138374045 is about 517.2313961550.
The spelling of 138374045 in words is "one hundred thirty-eight million, three hundred seventy-four thousand, forty-five".
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