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138421353601 = 472945135183
BaseRepresentation
bin1000000011101010001…
…1100011110010000001
3111020021211012100000001
42000322203203302001
54231441331303401
6143331230000001
713000132043446
oct2007243436201
9436254170001
10138421353601
11537822777a3
12229b1046001
131008c7c47bb
1469b1ad59cd
15390233e601
hex203a8e3c81

138421353601 has 4 divisors (see below), whose sum is σ = 141366488832. Its totient is φ = 135476218372.

The previous prime is 138421353599. The next prime is 138421353613. The reversal of 138421353601 is 106353124831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 138421353601 - 21 = 138421353599 is a prime.

It is a super-2 number, since 2×1384213536012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (138421353641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1472567545 + ... + 1472567638.

It is an arithmetic number, because the mean of its divisors is an integer number (35341622208).

Almost surely, 2138421353601 is an apocalyptic number.

It is an amenable number.

138421353601 is a deficient number, since it is larger than the sum of its proper divisors (2945135231).

138421353601 is an equidigital number, since it uses as much as digits as its factorization.

138421353601 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2945135230.

The product of its (nonzero) digits is 51840, while the sum is 37.

The spelling of 138421353601 in words is "one hundred thirty-eight billion, four hundred twenty-one million, three hundred fifty-three thousand, six hundred one".

Divisors: 1 47 2945135183 138421353601