Base | Representation |
---|---|
bin | 1000000011110100100… |
… | …0000000111110111111 |
3 | 111020101211022121111021 |
4 | 2000331020000332333 |
5 | 4232033400333311 |
6 | 143335410005011 |
7 | 13001164350250 |
oct | 2007510007677 |
9 | 436354277437 |
10 | 138464464831 |
11 | 537a4642910 |
12 | 22a03576767 |
13 | 1009870a4c4 |
14 | 69b7718b27 |
15 | 3906008171 |
hex | 203d200fbf |
138464464831 has 16 divisors (see below), whose sum is σ = 173872984320. Its totient is φ = 107118161280.
The previous prime is 138464464813. The next prime is 138464464837.
138464464831 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 138464464831 - 215 = 138464432063 is a prime.
It is a super-2 number, since 2×1384644648312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (138464464837) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6457786 + ... + 6479191.
It is an arithmetic number, because the mean of its divisors is an integer number (10867061520).
Almost surely, 2138464464831 is an apocalyptic number.
138464464831 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
138464464831 is a deficient number, since it is larger than the sum of its proper divisors (35408519489).
138464464831 is a wasteful number, since it uses less digits than its factorization.
138464464831 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12937134.
The product of its digits is 5308416, while the sum is 52.
The spelling of 138464464831 in words is "one hundred thirty-eight billion, four hundred sixty-four million, four hundred sixty-four thousand, eight hundred thirty-one".
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