Base | Representation |
---|---|
bin | 1000000100000111110… |
… | …1110101010101000111 |
3 | 111020121111010212010202 |
4 | 2001001331311111013 |
5 | 4232220143303420 |
6 | 143351430441115 |
7 | 13003201602236 |
oct | 2010175652507 |
9 | 436544125122 |
10 | 138545681735 |
11 | 5383647531a |
12 | 22a2680319b |
13 | 100ac4a5746 |
14 | 69c441ab1d |
15 | 390d1ec575 |
hex | 2041f75547 |
138545681735 has 4 divisors (see below), whose sum is σ = 166254818088. Its totient is φ = 110836545384.
The previous prime is 138545681731. The next prime is 138545681741. The reversal of 138545681735 is 537186545831.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 138545681735 - 22 = 138545681731 is a prime.
It is a super-2 number, since 2×1385456817352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (138545681731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13854568169 + ... + 13854568178.
It is an arithmetic number, because the mean of its divisors is an integer number (41563704522).
Almost surely, 2138545681735 is an apocalyptic number.
138545681735 is a deficient number, since it is larger than the sum of its proper divisors (27709136353).
138545681735 is an equidigital number, since it uses as much as digits as its factorization.
138545681735 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27709136352.
The product of its digits is 12096000, while the sum is 56.
The spelling of 138545681735 in words is "one hundred thirty-eight billion, five hundred forty-five million, six hundred eighty-one thousand, seven hundred thirty-five".
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