Base | Representation |
---|---|
bin | 11001110011100110… |
… | …00111111100111111 |
3 | 1022202112212212021221 |
4 | 30321303013330333 |
5 | 211333234330434 |
6 | 10210440134211 |
7 | 1000221125515 |
oct | 147163077477 |
9 | 38675785257 |
10 | 13854605119 |
11 | 596a621983 |
12 | 2827a67367 |
13 | 13ca4630c4 |
14 | 95606a4b5 |
15 | 5614b32b4 |
hex | 339cc7f3f |
13854605119 has 8 divisors (see below), whose sum is σ = 14245238448. Its totient is φ = 13464823680.
The previous prime is 13854605113. The next prime is 13854605129. The reversal of 13854605119 is 91150645831.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13854605119 - 217 = 13854474047 is a prime.
It is a super-3 number, since 3×138546051193 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a zygodrome in base 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13854605113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 179917 + ... + 245110.
It is an arithmetic number, because the mean of its divisors is an integer number (1780654806).
Almost surely, 213854605119 is an apocalyptic number.
13854605119 is a deficient number, since it is larger than the sum of its proper divisors (390633329).
13854605119 is an equidigital number, since it uses as much as digits as its factorization.
13854605119 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 425945.
The product of its (nonzero) digits is 129600, while the sum is 43.
The spelling of 13854605119 in words is "thirteen billion, eight hundred fifty-four million, six hundred five thousand, one hundred nineteen".
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