13880498212439 has 4 divisors (see below), whose sum is σ = 13880603365440. Its totient is φ = 13880393059440.

The previous prime is 13880498212391. The next prime is 13880498212459. The reversal of 13880498212439 is 93421289408831.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13880498212439 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13880498212459) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52378247 + ... + 52642584.

It is an arithmetic number, because the mean of its divisors is an integer number (3470150841360).

Almost surely, 2^{13880498212439} is an apocalyptic number.

13880498212439 is a deficient number, since it is larger than the sum of its proper divisors (105153001).

13880498212439 is a wasteful number, since it uses less digits than its factorization.

13880498212439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105153000.

The product of its (nonzero) digits is 23887872, while the sum is 62.

The spelling of 13880498212439 in words is "thirteen trillion, eight hundred eighty billion, four hundred ninety-eight million, two hundred twelve thousand, four hundred thirty-nine".