Base | Representation |
---|---|
bin | 10100001101101110000… |
… | …111111000100101100001 |
3 | 11220210120022002222212112 |
4 | 110031232013320211201 |
5 | 140224410212402103 |
6 | 2542053121205105 |
7 | 202234511104022 |
oct | 24155607704541 |
9 | 4823508088775 |
10 | 1389121997153 |
11 | 49613a1757a0 |
12 | 1a527a190795 |
13 | a0cbc0554b7 |
14 | 4b33ba14c49 |
15 | 2620316ccd8 |
hex | 1436e1f8961 |
1389121997153 has 16 divisors (see below), whose sum is σ = 1516972133376. Its totient is φ = 1261533373440.
The previous prime is 1389121997143. The next prime is 1389121997173. The reversal of 1389121997153 is 3517991219831.
It is a cyclic number.
It is not a de Polignac number, because 1389121997153 - 230 = 1388048255329 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1389121997092 and 1389121997101.
It is not an unprimeable number, because it can be changed into a prime (1389121997143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 94768001 + ... + 94782657.
It is an arithmetic number, because the mean of its divisors is an integer number (94810758336).
Almost surely, 21389121997153 is an apocalyptic number.
It is an amenable number.
1389121997153 is a deficient number, since it is larger than the sum of its proper divisors (127850136223).
1389121997153 is a wasteful number, since it uses less digits than its factorization.
1389121997153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22984.
The product of its digits is 3674160, while the sum is 59.
The spelling of 1389121997153 in words is "one trillion, three hundred eighty-nine billion, one hundred twenty-one million, nine hundred ninety-seven thousand, one hundred fifty-three".
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