Base | Representation |
---|---|
bin | 10100001101101110000… |
… | …111111000100101010111 |
3 | 11220210120022002222212011 |
4 | 110031232013320211113 |
5 | 140224410212402033 |
6 | 2542053121205051 |
7 | 202234511104006 |
oct | 24155607704527 |
9 | 4823508088764 |
10 | 1389121997143 |
11 | 49613a175791 |
12 | 1a527a190787 |
13 | a0cbc0554aa |
14 | 4b33ba14c3d |
15 | 2620316cccd |
hex | 1436e1f8957 |
1389121997143 has 2 divisors, whose sum is σ = 1389121997144. Its totient is φ = 1389121997142.
The previous prime is 1389121997071. The next prime is 1389121997173. The reversal of 1389121997143 is 3417991219831.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1389121997143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1389121997173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 694560998571 + 694560998572.
It is an arithmetic number, because the mean of its divisors is an integer number (694560998572).
Almost surely, 21389121997143 is an apocalyptic number.
1389121997143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1389121997143 is an equidigital number, since it uses as much as digits as its factorization.
1389121997143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2939328, while the sum is 58.
The spelling of 1389121997143 in words is "one trillion, three hundred eighty-nine billion, one hundred twenty-one million, nine hundred ninety-seven thousand, one hundred forty-three".
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