Base | Representation |
---|---|
bin | 1100101000110010100011… |
… | …1110111111100100010111 |
3 | 1211012100011221112110202120 |
4 | 3022030220332333210113 |
5 | 3310123232120221003 |
6 | 45315122043111023 |
7 | 2632605513052434 |
oct | 312145076774427 |
9 | 54170157473676 |
10 | 13894906804503 |
11 | 447788471940a |
12 | 1684b14212473 |
13 | 79a3901b537a |
14 | 360734c0ab8b |
15 | 19168999d853 |
hex | ca328fbf917 |
13894906804503 has 16 divisors (see below), whose sum is σ = 18690716528640. Its totient is φ = 9181186093184.
The previous prime is 13894906804501. The next prime is 13894906804507. The reversal of 13894906804503 is 30540860949831.
It is a cyclic number.
It is not a de Polignac number, because 13894906804503 - 21 = 13894906804501 is a prime.
It is a super-2 number, since 2×138949068045032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13894906804501) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36389188 + ... + 36769046.
It is an arithmetic number, because the mean of its divisors is an integer number (1168169783040).
Almost surely, 213894906804503 is an apocalyptic number.
13894906804503 is a deficient number, since it is larger than the sum of its proper divisors (4795809724137).
13894906804503 is a wasteful number, since it uses less digits than its factorization.
13894906804503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 487878.
The product of its (nonzero) digits is 22394880, while the sum is 60.
The spelling of 13894906804503 in words is "thirteen trillion, eight hundred ninety-four billion, nine hundred six million, eight hundred four thousand, five hundred three".
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