Base | Representation |
---|---|
bin | 1100101001010100000011… |
… | …1011110011010010000000 |
3 | 1211020012101121002202022000 |
4 | 3022111000323303102000 |
5 | 3310300141012234040 |
6 | 45323210211344000 |
7 | 2633344365506121 |
oct | 312250073632200 |
9 | 54205347082260 |
10 | 13903898555520 |
11 | 4480679295aa6 |
12 | 16868035b2000 |
13 | 79b194037abc |
14 | 360d490b6048 |
15 | 191a1409b130 |
hex | ca540ef3480 |
13903898555520 has 256 divisors, whose sum is σ = 49936541472000. Its totient is φ = 3655484743680.
The previous prime is 13903898555507. The next prime is 13903898555539. The reversal of 13903898555520 is 2555589830931.
13903898555520 is a `hidden beast` number, since 13 + 9 + 0 + 3 + 8 + 98 + 5 + 5 + 5 + 520 = 666.
It is a super-2 number, since 2×139038985555202 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4439485 + ... + 6893244.
It is an arithmetic number, because the mean of its divisors is an integer number (195064615125).
Almost surely, 213903898555520 is an apocalyptic number.
13903898555520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13903898555520 is an abundant number, since it is smaller than the sum of its proper divisors (36032642916480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13903898555520 is a wasteful number, since it uses less digits than its factorization.
13903898555520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11332828 (or 11332810 counting only the distinct ones).
The product of its (nonzero) digits is 58320000, while the sum is 63.
The spelling of 13903898555520 in words is "thirteen trillion, nine hundred three billion, eight hundred ninety-eight million, five hundred fifty-five thousand, five hundred twenty".
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