Base | Representation |
---|---|
bin | 1100101100001101100101… |
… | …1111001001000111111111 |
3 | 1211101221221112012012112022 |
4 | 3023003121133021013333 |
5 | 3312104140331101434 |
6 | 45402124213030355 |
7 | 2640056521046435 |
oct | 313033137110777 |
9 | 54357845165468 |
10 | 13953702597119 |
11 | 449a80638665a |
12 | 16943a29253bb |
13 | 7a2aa0306cbc |
14 | 363511796d55 |
15 | 192e7b63422e |
hex | cb0d97c91ff |
13953702597119 has 4 divisors (see below), whose sum is σ = 13953937500144. Its totient is φ = 13953467694096.
The previous prime is 13953702597061. The next prime is 13953702597137. The reversal of 13953702597119 is 91179520735931.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13953702597119 - 28 = 13953702596863 is a prime.
It is a super-2 number, since 2×139537025971192 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13953702590119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117362387 + ... + 117481220.
It is an arithmetic number, because the mean of its divisors is an integer number (3488484375036).
Almost surely, 213953702597119 is an apocalyptic number.
13953702597119 is a deficient number, since it is larger than the sum of its proper divisors (234903025).
13953702597119 is an equidigital number, since it uses as much as digits as its factorization.
13953702597119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234903024.
The product of its (nonzero) digits is 16074450, while the sum is 62.
The spelling of 13953702597119 in words is "thirteen trillion, nine hundred fifty-three billion, seven hundred two million, five hundred ninety-seven thousand, one hundred nineteen".
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