13961104413673 has 4 divisors (see below), whose sum is σ = 14258149188480. Its totient is φ = 13664059638868.

The previous prime is 13961104413667. The next prime is 13961104413689. The reversal of 13961104413673 is 37631440116931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13961104413673 is a prime.

It is a super-2 number, since 2×13961104413673² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13961104413623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148522387333 + ... + 148522387426.

It is an arithmetic number, because the mean of its divisors is an integer number (3564537297120).

Almost surely, 2^{13961104413673} is an apocalyptic number.

It is an amenable number.

13961104413673 is a deficient number, since it is larger than the sum of its proper divisors (297044774807).

13961104413673 is an equidigital number, since it uses as much as digits as its factorization.

13961104413673 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 297044774806.

The product of its (nonzero) digits is 979776, while the sum is 49.

The spelling of 13961104413673 in words is "thirteen trillion, nine hundred sixty-one billion, one hundred four million, four hundred thirteen thousand, six hundred seventy-three".