Base | Representation |
---|---|
bin | 1100101110100011101110… |
… | …1001000011010101000111 |
3 | 1211112210222012112000212012 |
4 | 3023220323221003111013 |
5 | 3313234210020131110 |
6 | 45432431241244435 |
7 | 2643014315643203 |
oct | 313507351032507 |
9 | 54483865460765 |
10 | 13994004067655 |
11 | 45059075229a7 |
12 | 16a016b79371b |
13 | 7a68239807a1 |
14 | 365455ddbb03 |
15 | 19403981a905 |
hex | cba3ba43547 |
13994004067655 has 16 divisors (see below), whose sum is σ = 16808087430144. Its totient is φ = 11185015699200.
The previous prime is 13994004067627. The next prime is 13994004067657. The reversal of 13994004067655 is 55676040049931.
It is not a de Polignac number, because 13994004067655 - 226 = 13993936958791 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13994004067594 and 13994004067603.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13994004067657) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 236944109 + ... + 237003161.
It is an arithmetic number, because the mean of its divisors is an integer number (1050505464384).
Almost surely, 213994004067655 is an apocalyptic number.
13994004067655 is a deficient number, since it is larger than the sum of its proper divisors (2814083362489).
13994004067655 is a wasteful number, since it uses less digits than its factorization.
13994004067655 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 101386.
The product of its (nonzero) digits is 24494400, while the sum is 59.
The spelling of 13994004067655 in words is "thirteen trillion, nine hundred ninety-four billion, four million, sixty-seven thousand, six hundred fifty-five".
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