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13994391840 = 253511131767179
BaseRepresentation
bin11010000100010000…
…10111100100100000
31100010021220202121220
431002020113210200
5212130031014330
610232352215040
71003536240132
oct150210274440
940107822556
1013994391840
115a315187a0
12286683a480
1314203c7340
1496a857052
1556d8c6710
hex342217920

13994391840 has 768 divisors, whose sum is σ = 55964805120. Its totient is φ = 2887188480.

The previous prime is 13994391833. The next prime is 13994391913. The reversal of 13994391840 is 4819349931.

It is a Harshad number since it is a multiple of its sum of digits (51).

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 78180871 + ... + 78181049.

It is an arithmetic number, because the mean of its divisors is an integer number (72870840).

Almost surely, 213994391840 is an apocalyptic number.

13994391840 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13994391840, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27982402560).

13994391840 is an abundant number, since it is smaller than the sum of its proper divisors (41970413280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13994391840 is a wasteful number, since it uses less digits than its factorization.

13994391840 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 305 (or 297 counting only the distinct ones).

The product of its (nonzero) digits is 839808, while the sum is 51.

The spelling of 13994391840 in words is "thirteen billion, nine hundred ninety-four million, three hundred ninety-one thousand, eight hundred forty".