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13994761103 = 43969318287
BaseRepresentation
bin11010000100010011…
…10001101110001111
31100010022121112011022
431002021301232033
5212130124323403
610232404144355
71003542335531
oct150211615617
940108545138
1013994761103
115a31750174
1228669980bb
1314204c643b
1496a911851
1556d94ad38
hex342271b8f

13994761103 has 4 divisors (see below), whose sum is σ = 13995123360. Its totient is φ = 13994398848.

The previous prime is 13994761073. The next prime is 13994761111. The reversal of 13994761103 is 30116749931.

13994761103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13994761103 - 210 = 13994760079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13994761133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115175 + ... + 203112.

It is an arithmetic number, because the mean of its divisors is an integer number (3498780840).

Almost surely, 213994761103 is an apocalyptic number.

13994761103 is a deficient number, since it is larger than the sum of its proper divisors (362257).

13994761103 is an equidigital number, since it uses as much as digits as its factorization.

13994761103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 362256.

The product of its (nonzero) digits is 122472, while the sum is 44.

The spelling of 13994761103 in words is "thirteen billion, nine hundred ninety-four million, seven hundred sixty-one thousand, one hundred three".

Divisors: 1 43969 318287 13994761103