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139954843 = 719993549
BaseRepresentation
bin10000101011110…
…00101010011011
3100202100102221201
420111320222123
5241312023333
621515415031
73316411420
oct1025705233
9322312851
10139954843
1172001166
123aa54477
1322cc2922
1414831d47
15c44817d
hex8578a9b

139954843 has 4 divisors (see below), whose sum is σ = 159948400. Its totient is φ = 119961288.

The previous prime is 139954781. The next prime is 139954847. The reversal of 139954843 is 348459931.

It is a happy number.

139954843 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 139954843 - 217 = 139823771 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 139954793 and 139954802.

It is not an unprimeable number, because it can be changed into a prime (139954847) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9996768 + ... + 9996781.

It is an arithmetic number, because the mean of its divisors is an integer number (39987100).

Almost surely, 2139954843 is an apocalyptic number.

139954843 is a deficient number, since it is larger than the sum of its proper divisors (19993557).

139954843 is an equidigital number, since it uses as much as digits as its factorization.

139954843 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19993556.

The product of its digits is 466560, while the sum is 46.

The square root of 139954843 is about 11830.2511807654. The cubic root of 139954843 is about 519.1935762158.

The spelling of 139954843 in words is "one hundred thirty-nine million, nine hundred fifty-four thousand, eight hundred forty-three".

Divisors: 1 7 19993549 139954843