140004213400111 has 4 divisors (see below), whose sum is σ = 140427186854824. Its totient is φ = 139581239945400.

The previous prime is 140004213400069. The next prime is 140004213400141. The reversal of 140004213400111 is 111004312400041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140004213400111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140004213400141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211486726860 + ... + 211486727521.

It is an arithmetic number, because the mean of its divisors is an integer number (35106796713706).

Almost surely, 2^{140004213400111} is an apocalyptic number.

140004213400111 is a deficient number, since it is larger than the sum of its proper divisors (422973454713).

140004213400111 is an equidigital number, since it uses as much as digits as its factorization.

140004213400111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 422973454712.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 140004213400111 its reverse (111004312400041), we get a palindrome (251008525800152).

The spelling of 140004213400111 in words is "one hundred forty trillion, four billion, two hundred thirteen million, four hundred thousand, one hundred eleven".