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140004493131 = 346668164377
BaseRepresentation
bin1000001001100011101…
…0110000011101001011
3111101101011011011011110
42002120322300131023
54243212122240011
6144152302101403
713054304361546
oct2023072603513
9441334134143
10140004493131
1154414982978
122317327a863
13102827a6159
146ac207b85d
15399630cba6
hex2098eb074b

140004493131 has 4 divisors (see below), whose sum is σ = 186672657512. Its totient is φ = 93336328752.

The previous prime is 140004493129. The next prime is 140004493169. The reversal of 140004493131 is 131394400041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 140004493131 - 21 = 140004493129 is a prime.

It is a super-2 number, since 2×1400044931312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140004493931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23334082186 + ... + 23334082191.

It is an arithmetic number, because the mean of its divisors is an integer number (46668164378).

Almost surely, 2140004493131 is an apocalyptic number.

140004493131 is a deficient number, since it is larger than the sum of its proper divisors (46668164381).

140004493131 is an equidigital number, since it uses as much as digits as its factorization.

140004493131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46668164380.

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 140004493131 its reverse (131394400041), we get a palindrome (271398893172).

The spelling of 140004493131 in words is "one hundred forty billion, four million, four hundred ninety-three thousand, one hundred thirty-one".

Divisors: 1 3 46668164377 140004493131