140010050314 has 4 divisors (see below), whose sum is σ = 210015075474. Its totient is φ = 70005025156.

The previous prime is 140010050263. The next prime is 140010050407. The reversal of 140010050314 is 413050010041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 84306026025 + 55704024289 = 290355^2 + 236017^2 .

It is a super-2 number, since 2×140010050314² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140010050291 and 140010050300.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35002512577 + ... + 35002512580.

Almost surely, 2^140010050314 is an apocalyptic number.

140010050314 is a deficient number, since it is larger than the sum of its proper divisors (70005025160).

140010050314 is an equidigital number, since it uses as much as digits as its factorization.

140010050314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70005025159.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 140010050314 its reverse (413050010041), we get a palindrome (553060060355).

The spelling of 140010050314 in words is "one hundred forty billion, ten million, fifty thousand, three hundred fourteen".