Base | Representation |
---|---|
bin | 11010000101000011… |
… | …11101101001000001 |
3 | 1100010202112122101021 |
4 | 31002201331221001 |
5 | 212133240221002 |
6 | 10233152105441 |
7 | 1003650253354 |
oct | 150241755101 |
9 | 40122478337 |
10 | 14001101377 |
11 | 5a3529076a |
12 | 2868b35281 |
13 | 1421906293 |
14 | 96b6c229b |
15 | 56e29e737 |
hex | 34287da41 |
14001101377 has 4 divisors (see below), whose sum is σ = 14238408240. Its totient is φ = 13763794516.
The previous prime is 14001101363. The next prime is 14001101407. The reversal of 14001101377 is 77310110041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14001101377 - 231 = 11853617729 is a prime.
It is a super-2 number, since 2×140011013772 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14001101977) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118653343 + ... + 118653460.
It is an arithmetic number, because the mean of its divisors is an integer number (3559602060).
Almost surely, 214001101377 is an apocalyptic number.
It is an amenable number.
14001101377 is a deficient number, since it is larger than the sum of its proper divisors (237306863).
14001101377 is an equidigital number, since it uses as much as digits as its factorization.
14001101377 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 237306862.
The product of its (nonzero) digits is 588, while the sum is 25.
The spelling of 14001101377 in words is "fourteen billion, one million, one hundred one thousand, three hundred seventy-seven".
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