Base | Representation |
---|---|
bin | 11010000101000011… |
… | …11110010000111111 |
3 | 1100010202112202220000 |
4 | 31002201332100333 |
5 | 212133240311220 |
6 | 10233152125343 |
7 | 1003650264000 |
oct | 150241762077 |
9 | 40122482800 |
10 | 14001103935 |
11 | 5a35292685 |
12 | 2868b36853 |
13 | 14219074b0 |
14 | 96b6c31a7 |
15 | 56e2a0390 |
hex | 34287e43f |
14001103935 has 160 divisors (see below), whose sum is σ = 31524662400. Its totient is φ = 5907396096.
The previous prime is 14001103913. The next prime is 14001103957. The reversal of 14001103935 is 53930110041.
It is an interprime number because it is at equal distance from previous prime (14001103913) and next prime (14001103957).
It is not a de Polignac number, because 14001103935 - 28 = 14001103679 is a prime.
It is a super-2 number, since 2×140011039352 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 14001103899 and 14001103908.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 1802019 + ... + 1809771.
It is an arithmetic number, because the mean of its divisors is an integer number (197029140).
Almost surely, 214001103935 is an apocalyptic number.
14001103935 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14001103935 is an abundant number, since it is smaller than the sum of its proper divisors (17523558465).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14001103935 is an equidigital number, since it uses as much as digits as its factorization.
14001103935 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7804 (or 7781 counting only the distinct ones).
The product of its (nonzero) digits is 1620, while the sum is 27.
Adding to 14001103935 its reverse (53930110041), we get a palindrome (67931213976).
The spelling of 14001103935 in words is "fourteen billion, one million, one hundred three thousand, nine hundred thirty-five".
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