14001222413041 has 4 divisors (see below), whose sum is σ = 14609971213632. Its totient is φ = 13392473612452.

The previous prime is 14001222412999. The next prime is 14001222413069. The reversal of 14001222413041 is 14031422210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14001222413041 - 2⁷ = 14001222412913 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14001222412997 and 14001222413015.

It is not an unprimeable number, because it can be changed into a prime (14001222413071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 304374400261 + ... + 304374400306.

It is an arithmetic number, because the mean of its divisors is an integer number (3652492803408).

Almost surely, 2^{14001222413041} is an apocalyptic number.

It is an amenable number.

14001222413041 is a deficient number, since it is larger than the sum of its proper divisors (608748800591).

14001222413041 is an equidigital number, since it uses as much as digits as its factorization.

14001222413041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 608748800590.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 14001222413041 its reverse (14031422210041), we get a palindrome (28032644623082).

The spelling of 14001222413041 in words is "fourteen trillion, one billion, two hundred twenty-two million, four hundred thirteen thousand, forty-one".