14001230144113 has 4 divisors (see below), whose sum is σ = 14038172704240. Its totient is φ = 13964287583988.

The previous prime is 14001230144081. The next prime is 14001230144117. The reversal of 14001230144113 is 31144103210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14001230144113 - 2⁵ = 14001230144081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14001230144117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18471279495 + ... + 18471280252.

It is an arithmetic number, because the mean of its divisors is an integer number (3509543176060).

Almost surely, 2^{14001230144113} is an apocalyptic number.

It is an amenable number.

14001230144113 is a deficient number, since it is larger than the sum of its proper divisors (36942560127).

14001230144113 is an equidigital number, since it uses as much as digits as its factorization.

14001230144113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36942560126.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14001230144113 its reverse (31144103210041), we get a palindrome (45145333354154).

The spelling of 14001230144113 in words is "fourteen trillion, one billion, two hundred thirty million, one hundred forty-four thousand, one hundred thirteen".