Base | Representation |
---|---|
bin | 1100101110111110101010… |
… | …0010011011100100101001 |
3 | 1211120111122000121200211021 |
4 | 3023233222202123210221 |
5 | 3313344011211441131 |
6 | 45440024445132441 |
7 | 2643361420340353 |
oct | 313575242334451 |
9 | 54514560550737 |
10 | 14001233312041 |
11 | 4508987214238 |
12 | 16a164885a121 |
13 | 7a740660caa1 |
14 | 3659401900d3 |
15 | 19430e318e11 |
hex | cbbea89b929 |
14001233312041 has 16 divisors (see below), whose sum is σ = 14320235548864. Its totient is φ = 13685707024704.
The previous prime is 14001233311979. The next prime is 14001233312071. The reversal of 14001233312041 is 14021333210041.
It is a cyclic number.
It is not a de Polignac number, because 14001233312041 - 211 = 14001233309993 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14001233311997 and 14001233312015.
It is not an unprimeable number, because it can be changed into a prime (14001233312071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6802486 + ... + 8618368.
It is an arithmetic number, because the mean of its divisors is an integer number (895014721804).
Almost surely, 214001233312041 is an apocalyptic number.
It is an amenable number.
14001233312041 is a deficient number, since it is larger than the sum of its proper divisors (319002236823).
14001233312041 is a wasteful number, since it uses less digits than its factorization.
14001233312041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1816840.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 14001233312041 its reverse (14021333210041), we get a palindrome (28022566522082).
The spelling of 14001233312041 in words is "fourteen trillion, one billion, two hundred thirty-three million, three hundred twelve thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •