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14001234410113 = 25411550991083
BaseRepresentation
bin1100101110111110101010…
…0110100111101010000001
31211120111122002200111002121
43023233222212213222001
53313344012002110423
645440024524444241
72643361432562626
oct313575246475201
954514562614077
1014001234410113
1145089878a4235
1216a16490a9681
137a7406905832
1436594039834d
1519430e48445d
hexcbbea9a7a81

14001234410113 has 4 divisors (see below), whose sum is σ = 14001785426608. Its totient is φ = 14000683393620.

The previous prime is 14001234410069. The next prime is 14001234410143. The reversal of 14001234410113 is 31101443210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14001234410113 - 29 = 14001234409601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14001234410143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 275470131 + ... + 275520952.

It is an arithmetic number, because the mean of its divisors is an integer number (3500446356652).

Almost surely, 214001234410113 is an apocalyptic number.

It is an amenable number.

14001234410113 is a deficient number, since it is larger than the sum of its proper divisors (551016495).

14001234410113 is an equidigital number, since it uses as much as digits as its factorization.

14001234410113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 551016494.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14001234410113 its reverse (31101443210041), we get a palindrome (45102677620154).

The spelling of 14001234410113 in words is "fourteen trillion, one billion, two hundred thirty-four million, four hundred ten thousand, one hundred thirteen".

Divisors: 1 25411 550991083 14001234410113