Base | Representation |
---|---|
bin | 10100010111111101110… |
… | …111001001010001100001 |
3 | 11221211222000022100112102 |
4 | 110113331313021101201 |
5 | 140414423101302003 |
6 | 2551112520540145 |
7 | 203104236032531 |
oct | 24277567112141 |
9 | 4854860270472 |
10 | 1400123462753 |
11 | 49a875214724 |
12 | 1a742a621655 |
13 | a2053373c62 |
14 | 4baa2b874c1 |
15 | 26648deb588 |
hex | 145fddc9461 |
1400123462753 has 16 divisors (see below), whose sum is σ = 1457211840000. Its totient is φ = 1344072854592.
The previous prime is 1400123462737. The next prime is 1400123462797. The reversal of 1400123462753 is 3572643210041.
It is a cyclic number.
It is not a de Polignac number, because 1400123462753 - 24 = 1400123462737 is a prime.
It is a super-3 number, since 3×14001234627533 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1400123461753) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3918083 + ... + 4260471.
It is an arithmetic number, because the mean of its divisors is an integer number (91075740000).
Almost surely, 21400123462753 is an apocalyptic number.
It is an amenable number.
1400123462753 is a deficient number, since it is larger than the sum of its proper divisors (57088377247).
1400123462753 is a wasteful number, since it uses less digits than its factorization.
1400123462753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 343904.
The product of its (nonzero) digits is 120960, while the sum is 38.
Adding to 1400123462753 its reverse (3572643210041), we get a palindrome (4972766672794).
The spelling of 1400123462753 in words is "one trillion, four hundred billion, one hundred twenty-three million, four hundred sixty-two thousand, seven hundred fifty-three".
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