14001243204401 has 4 divisors (see below), whose sum is σ = 14299141996032. Its totient is φ = 13703344412772.

The previous prime is 14001243204371. The next prime is 14001243204419. The reversal of 14001243204401 is 10440234210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14001243204401 - 2⁶ = 14001243204337 is a prime.

It is a super-3 number, since 3×14001243204401³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14001243204451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148949395745 + ... + 148949395838.

It is an arithmetic number, because the mean of its divisors is an integer number (3574785499008).

Almost surely, 2^{14001243204401} is an apocalyptic number.

It is an amenable number.

14001243204401 is a deficient number, since it is larger than the sum of its proper divisors (297898791631).

14001243204401 is an equidigital number, since it uses as much as digits as its factorization.

14001243204401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 297898791630.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 14001243204401 its reverse (10440234210041), we get a palindrome (24441477414442).

The spelling of 14001243204401 in words is "fourteen trillion, one billion, two hundred forty-three million, two hundred four thousand, four hundred one".