14001300344401 has 4 divisors (see below), whose sum is σ = 14610052533312. Its totient is φ = 13392548155492.

The previous prime is 14001300344359. The next prime is 14001300344413. The reversal of 14001300344401 is 10444300310041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14001300344401 - 2⁹ = 14001300343889 is a prime.

It is a super-2 number, since 2×14001300344401² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14001300344461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 304376094421 + ... + 304376094466.

It is an arithmetic number, because the mean of its divisors is an integer number (3652513133328).

Almost surely, 2^{14001300344401} is an apocalyptic number.

It is an amenable number.

14001300344401 is a deficient number, since it is larger than the sum of its proper divisors (608752188911).

14001300344401 is an equidigital number, since it uses as much as digits as its factorization.

14001300344401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 608752188910.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14001300344401 its reverse (10444300310041), we get a palindrome (24445600654442).

The spelling of 14001300344401 in words is "fourteen trillion, one billion, three hundred million, three hundred forty-four thousand, four hundred one".