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1400130374515 = 51070926148667
BaseRepresentation
bin10100010111111110010…
…001100000101101110011
311221211222111022111200121
4110113332101200231303
5140414431333441030
62551113325031111
7203104351550455
oct24277621405563
94854874274617
101400130374515
1149a879105624
121a74309b5497
13a2054923c62
144baa3a662d5
152664981447a
hex145fe460b73

1400130374515 has 8 divisors (see below), whose sum is σ = 1680313405680. Its totient is φ = 1119999662112.

The previous prime is 1400130374473. The next prime is 1400130374633. The reversal of 1400130374515 is 5154730310041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1400130374515 - 211 = 1400130372467 is a prime.

It is a super-2 number, since 2×14001303745152 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13020789 + ... + 13127878.

It is an arithmetic number, because the mean of its divisors is an integer number (210039175710).

Almost surely, 21400130374515 is an apocalyptic number.

1400130374515 is a deficient number, since it is larger than the sum of its proper divisors (280183031165).

1400130374515 is a wasteful number, since it uses less digits than its factorization.

1400130374515 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26159381.

The product of its (nonzero) digits is 25200, while the sum is 34.

Adding to 1400130374515 its reverse (5154730310041), we get a palindrome (6554860684556).

The spelling of 1400130374515 in words is "one trillion, four hundred billion, one hundred thirty million, three hundred seventy-four thousand, five hundred fifteen".

Divisors: 1 5 10709 53545 26148667 130743335 280026074903 1400130374515